A vessel of 120mL, capacity contains a certain amount of gas at 35°C and 1.2bar pressure. The gas is transferred to another vessel of volume 180 mL at 35°C. What would be its pressure?

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0.8 bar

1 bar

0.6 bar

0.2 bar

answer is A.

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Detailed Solution

p1=1.2 bar, p2=?,V1=120 mL,V2=180 mL From Boyle's law, p1V1=p2V2p2=p1V1V2p2=1.2bar×120 mL180 mL=0.8bar

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