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Volume of CO2 obtained at STP by the complete decomposition of 8.4 g of MgCO3 (90% pure) at STP will be

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a

2.02 L

b

1.46 L

c

2.91 L

d

3.42 L

answer is A.

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Detailed Solution

MgCO3(s)⟶ΔMgO(s)+CO2(g) 84g 1 mole Volume of CO2 obtain at STP=8.484×90100×22.4 L =2.016L≃2.02L

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Volume of CO2 obtained at STP by the complete decomposition of 8.4 g of MgCO3 (90% pure) at STP will be