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Q.

The volume of gas A is twice than that of gas B. The compressibility factor of gas A is thrice than that of gas B at same temperature. The pressures of the gases for equal number of moles are

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a

2PA=3PB

b

3PA=2PB

c

PA=3PB

d

PA=2PB

answer is A.

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Detailed Solution

Z = PV/nRT⇒⇒ P =ZnRTVat constant T and mol(n),P ∝ ZV⇒PAPB=ZAZA×VBVA= (31)×(12) = 32∴ 2PA = 3PB
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