The volume of gas A is twice than that of gas B. The compressibility factor of gas A is thrice than that of gas B at same temperature. The pressures of the gases for equal number of moles are
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a
2PA=3PB
b
3PA=2PB
c
PA=3PB
d
PA=2PB
answer is A.
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Detailed Solution
Z = PV/nRT⇒⇒ P =ZnRTVat constant T and mol(n),P ∝ ZV⇒PAPB=ZAZA×VBVA= (31)×(12) = 32∴ 2PA = 3PB