The volume occupied by 8.8 g of CO₂ at 31.1°C and 1 bar pressure (in L) is:

$\text{ No. of mole of }{\mathrm{CO}}_2=\frac{8.8}{44}=0.2\mathrm{mole},\mathrm{T}=304.1\mathrm{K},\mathrm{P}=1\mathrm{bar}$

$\mathrm{V}=\frac{\mathrm{nRT}}{\mathrm{P}}=\frac{0.2\times 0.083\times 304.1}{1}=5\mathrm{L}$