The volume occupied by 1.8 g of water vapour at 374°C and 1 bar pressure will be[Use R = 0.083 bar L K-1 mol-1]

According to ideal gas equation,pV = nRTor V= nRTp = wM.wtRTp   .....(i)   [ n = wM.wt]Given, w = 1.8g, T = 374° C             = (374 + 273)K = 647 K           p = 1 bar,           R = 0.083 bar LK-1 mol-1On substituting the given values in Eq.(i), we getV = 1.8g18 g mol-1×0.082 bar LK-1 mol-1×647 K1 bar    = 5.3 L