Questions
The volume of oxygen liberated from 0.68 g of is
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a
112 ml
b
224 ml
c
56 ml
d
336 ml
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Correct option is B
We know that2H2O2 → 2H2O + O2 2 × 34 g 22400 ml ∵ 2 × 34 g = 68 g of H2O2 22400 ml O2 at STP ∴ 0.68 g of H2O2 liberates = 0.68 × 2240068 = 224 mlSimilar Questions
100 cm3 of a given sample of H2O2, gives 1000 cm3 of O2 at STP. The given sample is
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