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Q.

The volume of oxygen liberated from 0.68 g of H2O2 is

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a

112 ml

b

224 ml

c

56 ml

d

336 ml

answer is B.

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Detailed Solution

We know that2H2O2 →  2H2O + O2 2 × 34 g       22400 ml ∵   2 × 34 g = 68 g of H2O2  22400 ml O2 at STP ∴   0.68 g of H2O2  liberates = 0.68 × 2240068 = 224 ml
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The volume of oxygen liberated from 0.68 g of H2O2 is