First slide

Hydrogen Peroxide

Question

The volume of oxygen liberated from 0.68 g of $H_{2} O_{2}$ is

Moderate

A

112 ml
B

224 ml
C

56 ml
D

336 ml

Solution

We know that
$2 H_{2} O_{2} \overset{}{\to} 2 H_{2} O + O_{2} 2 \times 34 g 22400 ml ∵ 2 \times 34 g = 68 g of H_{2} O_{2} 22400 ml O_{2} at STP ∴ 0.68 g of H_{2} O_{2} liberates = \frac{0.68 \times 22400}{68} = 224 ml$

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