The volume of oxygen liberated from 0.68 g of H2O2 is

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112 ml

224 ml

56 ml

336 ml

answer is B.

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Detailed Solution

We know that2H2O2 → 2H2O + O2 2 × 34 g 22400 ml ∵ 2 × 34 g = 68 g of H2O2 22400 ml O2 at STP ∴ 0.68 g of H2O2 liberates = 0.68 × 2240068 = 224 ml

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