First slide

Hydrogen Peroxide

Question

Volume strength and normality of perhydrol are respectively

Easy

A

100 vol ; 8.9 N
B

30 vol ; 17.8 N
C

100 vol ; 17.8 N
D

30 vol ; 8.9 N

Solution

$30 % (\frac{W}{V}) H_{2} O_{2}$ solution is perhydrol
$3.035 % (\frac{W}{V}) H_{2} O_{2}$ solution is 10 volume H₂O₂
Thus
$\begin{matrix} 10 vol H_{2} O_{2} = 3.035 % (\frac{W}{V}) H_{2} O_{2} \\ ? = 30 % (\frac{W}{V}) H_{2} O_{2} \end{matrix}$
Perhydrol is 100 vol H₂O₂ solution.
Normality of perhydrol = $\frac{30}{17} \times \frac{1000}{100} = 17 .8 N$ .

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