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The volume of water in ml that must be added to mixture of 250 ml of 0.6 M HCl and 750 ml of 0.2 HCl to obtain 0.25 M solution of HCl is ?

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answer is 200.

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Detailed Solution

M1V1+M2V2=M3V3 V3=M1V1+M2V2M3=0.6×250+0.2×750/0.25=1200 mlFinal volume = 1200 mlInitial volume = 250 + 750 = 1000 mlTherefore, volume added = 200 ml
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The volume of water in ml that must be added to mixture of 250 ml of 0.6 M HCl and 750 ml of 0.2 HCl to obtain 0.25 M solution of HCl is ?