Q.

The volumes of 4N HCl and 10N HCl required to make 1L of 6 N HCl are

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0.75L of 4 N HCl and 0.25L of 10 N HCl

0.25L of 4 N HCl and 0.75L of 10 N HCl

0.67L of 4 N HCl and 0.33L of 10 N HCl

0.80L of 4 N HCl and 0.20L of 10 N HCl

answer is C.

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Detailed Solution

solutions mixed are 4N HCl and 10N HCl to form 1l of 6N HClTotal volume of 6N solution = 1lit4N HCl sol. 10N HCl sol.V1= v l V2= (1-v) lN1= 4 N2=10 Resultantnormality ,N=V1N1+V2N2V1+V26=v(4)+(1-v)101 6= 4v+10-10v 6v=4V=23L=0.67L V1=0.67 V2= 1-0.67 = 0.33 L

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