The VSEPR model considers double and triple bonds to have slightly greater repulsive effects than single bonds because of the repulsive effect of r electrons. 
Consider following molecule for given question

${\left({\mathrm{CH}}_3\right)}_2\mathrm{C}={\mathrm{CH}}_2$

Which type of overlapping is not observed in given molecule?

• A

  ${\mathrm{sp}}^3-\mathrm{s}$

• B

  ${\mathrm{sp}}^2-\mathrm{s}$

• C

  $\mathrm{sp}-\mathrm{s}$

• D

  ${\mathrm{sp}}^2-{\mathrm{sp}}^3$

$\text{ Number of }\sigma \text{-bonds and }\pi \text{-bonds in given molecule respectively are : }$

• A

  $11\mathrm{\sigma },1\mathrm{\pi }$

• B

  $10\mathrm{\sigma },1\mathrm{\pi }$

• C

  $11\mathrm{\sigma },2\mathrm{\pi }$

• D

  $12\mathrm{\sigma },2\mathrm{\pi }$

Select which is larger bond angle in given molecule. 

• A

  ${\mathrm{CH}}_3-\stackrel{\wedge }{\mathrm{C}}-{\mathrm{CH}}_3$

• B

  ${\mathrm{H}}_3\mathrm{C}-\stackrel{\wedge }{\mathrm{C}}={\stackrel{\bullet }{\mathrm{C}}\mathrm{H}}_2$

• C

  $\stackrel{ }{\mathrm{H}}-\stackrel{\wedge }{\mathrm{C}}-\mathrm{H}$

• D

  All are same

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