Q.
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By Expert Faculty of Sri Chaitanya
a
sp3−s
b
sp2−s
c
sp−s
d
sp2−sp3
e
11σ,1π
f
10σ,1π
g
11σ,2π
h
12σ,2π
i
CH3−C∧−CH3
j
H3C−C∧=C∙H2
k
H −C∧−H
l
All are same
answer is