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A 600 W mercury lamp emits monochromatic radiation of wavelength 331.3 nm. How many photons are emitted from the lamp per second?
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Correct option is C
600W=600Js-1∴ Energy emitted per second = 600 JEnergy of one photon =hcλ=6.626×10-34Js×108ms-1313.3×10-9m=6.394×10-19Photon emiited per second =6006.344×10-19≈1×1021Talk to our academic expert!
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