A 600 W mercury lamp emits monochromatic radiation of wavelength 331.3 nm. How many photons are emitted from the lamp per second?
h=6.626×10−34Js; velocity of light =3×108ms−
1×1019
1×1020
1×1021
1×1023
600W=600Js-1∴ Energy emitted per second = 600 JEnergy of one photon =hcλ=6.626×10-34Js×108ms-1313.3×10-9m=6.394×10-19Photon emiited per second =6006.344×10-19≈1×1021