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Q.

For water Δvap H = 41 kJ mol−1 at 373 K and 1 bar pressure. Assuming that water vapour is an ideal gas that occupies a much larger volume than liquid water, the internal energy change during evaporation of water is nearly___________ kJ mol−1[Use : R = 8.3 J mol−1 K−1]

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a

41kJ mol−1

b

38 kJ/mol

c

44kJ mol−1

d

Zero kJ mol−1

answer is B.

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Detailed Solution

H2O(l) → H2O(g) : ΔH = 41 kJ/mol⇒ From the relation : ΔH = ΔU + ΔngRT⇒⇒ 41kJ/mol = ΔU + (1) × 8.31000 × 373ΔU = 41 − 3.0959 = 38 kJ/mol
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