Wave length of second line of Balmer series in Hydrogen spectrum is 'λ1'. Wave length of first line of Lyman series in Hydrogen spectrum is 'λ2'. λ1 : λ2 will be
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a
1 : 4
b
4 : 1
c
1 : 2
d
2 : 1
answer is B.
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Detailed Solution
ν¯=1λ=RH1n12−1n22Second line of Balmer series :n1 = 2 , n2 = 2+2 ;ν¯=1λ=RH122−142 ν¯=1λ=RH316 ∴λ1=163RHFirst line of Lyman series :n1 = 1 , n2 = 1+1 ;ν¯=1λ=RH112−122 ν¯=1λ=RH34 ∴λ2=43RH λ1:λ2=163RH:43RH λ1:λ2=4:1
Wave length of second line of Balmer series in Hydrogen spectrum is 'λ1'. Wave length of first line of Lyman series in Hydrogen spectrum is 'λ2'. λ1 : λ2 will be