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Q.

Wave length of second line of Balmer series in Hydrogen spectrum is 'λ1'. Wave length of first line of Lyman series in Hydrogen spectrum is 'λ2'.   λ1 : λ2 will be

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a

1 : 4

b

4 : 1

c

1 : 2

d

2 : 1

answer is B.

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Detailed Solution

ν¯=1λ=RH1n12−1n22Second line of Balmer series :n1 = 2 , n2 = 2+2 ;ν¯=1λ=RH122−142 ν¯=1λ=RH316 ∴λ1=163RHFirst line of Lyman series :n1 = 1 , n2 = 1+1 ;ν¯=1λ=RH112−122 ν¯=1λ=RH34 ∴λ2=43RH λ1:λ2=163RH:43RH λ1:λ2=4:1
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Wave length of second line of Balmer series in Hydrogen spectrum is 'λ1'. Wave length of first line of Lyman series in Hydrogen spectrum is 'λ2'.   λ1 : λ2 will be