The wavelength of certain radiation is 6625 Ao. Then the number of quantas present in 1J of energy of that radiation is

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3.3×10−19

3.3×1018

6×1010

3.3×1020

answer is B.

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Detailed Solution

E=nhcλ; n= Eλhc; n= 1×6625×10-10m6.625×10-34J.s×3×108m/s