Q.
Wavelength of high energy transition of H-atoms is 9.21 nm. Calculate the corresponding wavelength of He atoms.
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answer is 22.8.
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Detailed Solution
1λ=RHZ21n12−1n22∴ 191.2=RH112−1n2Since RH= constant λHeλH=ZH2ZHe2=1222=14or λHe=λH4=91.24=22.8nm.
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