Q.
The wavelength (in nanometer) associated with a proton (mass = 1.67×10-27 Kg/atom) at the velocity of 1.0×10-3 m/sec
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a
0.032 nm
b
0.400 nm
c
2.500 nm
d
14.000 nm
answer is B.
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Detailed Solution
By de-Broglie's equationλ=hmv=6.62×10−34Jskgm2s−11.67×10−27kg×1.0×10−3ms−1=4.0×10−10m=0.4×10−9m=0.4nm Note 1J=1kgm2s−2
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