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Q.

The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097  ×  107 m−1)

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a

406 nm

b

192 nm

c

91 nm

d

9.1  ×  10−8 nm

answer is C.

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Detailed Solution

1λ =R 1n12 −1n22 =1λ =  1.097  ×  107 m−1 11 2 −1∞2 ∴     λ  =  91  ×  10−9 mWe  know   10−9  =  1nm  So  λ=91  nm
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