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Q.

The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state 1,would be (Rydberg constant=1.097×107 m−1 )

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a

406 nm

b

192 nm

c

91 nm

d

9.1×10−8 nm

answer is C.

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Detailed Solution

1λ=R(1n11−1n22) 1λ=1.097×107(11−1∞)=1.097×107 λ=91.15×10−9m≈91 nm

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The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state 1,would be (Rydberg constant=1.097×107 m−1 )