Q.

We know that the relationship between Kc and Kp is Kp = Kc(RT)∆n What would be the value of∆n for the reaction NH4Cl(s) ⇆ NH3(g) + HCl(g)

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answer is 2.

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Detailed Solution

The relationship between Kp and Kc isKp = Kc (RT) ∆nWhere ∆n = (number of moles of gaseous products) – (number of moles of gaseous reactants)For the reaction,NH4Cl (s) ⇆ NH3(g) + HCl(g)∆n = 2 – 0 = 2
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We know that the relationship between Kc and Kp is Kp = Kc(RT)∆n What would be the value of∆n for the reaction NH4Cl(s) ⇆ NH3(g) + HCl(g)