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Q.

A weak acid (HA) is 4% ionised at 1 M. Per cent ionisation is____1% in the presence of A- of

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a

0.04 M

b

0.16 M

c

0.02 M

d

0.10 M

answer is B.

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Detailed Solution

HA⇌H++A− Ka=C⋅x2=1×41002=1.6×10−3 Ka=H+A−[HA] H+=C⋅x=1×0.01=0.01M ∴1.6×10−3=0.01A−1 A−=0.16M
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