First slide

Faraday's Laws

Question

The weight in grams of O₂ formed at Pt anode during the electrolysis of aq. K₂SO₄ solution during the passage of one coulomb of electricity is

Easy

Solution

The mass deposited for one Coulomb is called as electrochemical equivalent weight.
$e.c.e = \frac{{Eq.wt}}{{96500}}$

$= \frac{8}{{96500}}$

Eq.Wt of oxygen =8

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