The weight of KMnO4 that can oxidise 100ml of. 0.2M oxalic acid in acidic medium is [Mol. wt of KMnO4 = 158]

KMnO4                                                                                              n-factor in acidic medium = 5  MnO4-→Mn+2  Oxalic acidn-factor = 2C2O4-2→2CO2GEW=1585gV= 100ml N = 0.2(2) = 0.4NAt neutralization point , V1N1= V2N2WGEW=VN1000     W1585=100(0.4)1000                                         W=1.264g