Q.

The weight of MgCO3 required for the preparation of 1.2 gm of MgSO4 is

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a

0.84 gm

b

0.42gm

c

1.68 gm

d

1.26 gm

answer is A.

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Detailed Solution

MgCO3+H2SO4→MgSO4+CO2+H2O                120 gm MgSO4 obtained from →  84 gm MgCO3               1.20 gm MgSO4 obtained from → ?                                                                   =84120×1.2=0.84 gm
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