Weight of 112 ml of oxygen at NTP on liquefaction would be
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a
0.32 g
b
0.64 g
c
0.16 g
d
0.96 g
answer is C.
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Detailed Solution
22400 ml is the volume of O2 at NTP = 32 gm of O21 ml is the volume of O2 at NTP = 3222400112 ml is the volume of O2 at NTP = 3222400 x 112 = 0.16 g of O2