Q.

The weight of one mole of sodium carbonate (Na2CO3) is

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a

110 g

b

109 g

c

108 g

d

106 g

answer is D.

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Detailed Solution

Na2CO3 = 2 × 23 +12+3 ×16 = 106g
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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Best Books for NEET
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