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Q.

The weight of oxygen required to completely react with 9gm of Al is

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a

8 g

b

16 g

c

32 g

d

24 g

answer is A.

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Detailed Solution

2Al+32O2→Al2O3 2×27gm  Al  →32×32  gm  O2  9  gm  Al→  ?=32×322×27×9=8gm
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