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Weight of 40% pure Magnesite required to neutralize two moles of HCl will be

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By Expert Faculty of Sri Chaitanya
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a
33.6 g
b
210 g
c
180 g
d
67.2 g
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detailed solution

Correct option is B

MgCO3+2HCl →MgCl2+H2O+CO2; 84 g        2 molesbut the purity is only 40%, more amount of magnesite is required,Weight of magnesite required = 84×10040=210 grams ;

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