Q.
The weight of a pure sample of KClO3 to be decomposed in order to get 0.45 mole of O2 is
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a
2.45 gm
b
12.25 gm
c
9.9 gm
d
36.75 gm
answer is D.
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Detailed Solution
2KClO3→2KCl+3O2 3 mole O2→2×122.5 gm KClO3 0.45 mole O2→? =2×122.53×0.45=36.75 gm
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