Q.

The weight of a pure sample of KClO3 to be decomposed in order to get 0.45 mole of  O2  is

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a

2.45 gm

b

12.25 gm

c

9.9 gm

d

36.75 gm

answer is D.

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Detailed Solution

2KClO3→2KCl+3O2 3 mole  O2→2×122.5 gm KClO3  0.45 mole O2→?  =2×122.53×0.45=36.75 gm
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