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Q.

What is the activation energy for the decomposition of N2O5 as N2O5⇌2NO2+12O2If the values of the rate constants are 3.45×10−3 and 6.9×10−3 at 27oC and 67oC respectively.

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a

102×102 kJ

b

488.5 kJ

c

112 kJ

d

14.7 kJ

answer is D.

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Detailed Solution

log⁡6.9×10−33.45×10−3=Ea(340−300)8.314×10−3×2.303×300×340∴ Ea=0.301×8.314×10−3×2.303×300×34040          =14.7 KJ
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