What is the amount of chlorine evolved when 2 amperes of current is passed for 30 minutes in an aqueous solution of NaCl ?
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answer is 2.
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Detailed Solution
Charge (Q) passed= Current (I) in amperes x time (t) in seconds =2 amperes ×30min×60sec1min=3600 coulombs (∵ Ampere x sec = Coulomb). NaCl⇌Na++Cl−Cl−⇌1/2Cl2+1e−1/2×(2×35.5)=35.5g96500 C produce chlorine =35.5g(= g. equivalent of chlorine )3600 C produce chlorine =35.5g96500C×3600C=1.32g