What are the possible intermediates in the following reaction?

${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}={\mathrm{CH}}_2\frac{\left(1\right){\mathrm{Br}}_2+{\mathrm{CCl}}_4}{\left(2\right){\mathrm{NaNH}}_2; \mathrm{\Delta }}⟶{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{C}\equiv \mathrm{CH}$

• A

  ${\mathrm{CH}}_3-\underset{\oplus }{\mathrm{CH}}-\mathrm{CH}=\mathrm{CH}-\mathrm{Br}$

• B

  

• C

  ${\mathrm{CH}}_3{\mathrm{CH}}_2-\mathrm{CH}=\mathrm{CHBr}$

• D