Covalent Bonding

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By Expert Faculty of Sri Chaitanya

Question

What is the bond order of carbon monoxide?

Easy

Solution

$(σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} π 2 p_{x}^{2} \equiv π 2 p_{y}^{2} σ 2 p_{z}^{2})$
$Bond order = \frac{1}{2} (N_{b} - N_{a}) = \frac{1}{2} (10 - 4) = 3.0$

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