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Q.

What is the compressibility factor (Z) for 0.02 mole of a van der Waals' gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible.Given : RT = 20 L atm mol-1 and a = 1000 atm L2 mol2

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a

2

b

1

c

0.02

d

0.5

answer is D.

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Detailed Solution

0.1+1000×(0.02)2V2V=20×0.02=0.1V2−0.4V+0.4=0=V2−4V+4=0⇒ V=2LZ=PVnRT=0.1×220×0.02=0.5
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