What is the correct increasing order of extent of deprotonation of the following acids in its aqueous solution?I CH32CHOOH II CH3CH2COOHIII Cl2CHCH2COOH IV CH3CCl2COOH
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a
II < l < III < IV
b
IV < III < I < II
c
I < II < III < IV
d
I < IV < III < II
answer is C.
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Detailed Solution
Electron withdrawing group (Cl) increases acidic strength while electron donating group −CH3 decreases acidic strength. Also magnitude of inductive effect decreases drastically on increasing distance, IV is stronger acid than III.Two methyl groups (in I) gives greater +I-effect than onemethyl group (in II), hence I is a weaker acid than II.Two -Cl from closer position in IV exert greater −I-effect than the same from larger distance in III, hence IV is stronger acid than III.
What is the correct increasing order of extent of deprotonation of the following acids in its aqueous solution?I CH32CHOOH II CH3CH2COOHIII Cl2CHCH2COOH IV CH3CCl2COOH