What is the correct increasing order of reactivity of the followings in SN2 reaction?I. CH2=CH−CH2−Br II. CH3CH2CH(Cl)CH3 III. CH3CH2CH2−I IV. p−O2N−C6H4−CH2Cl

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I< ll < lll < IV

III < II < I < IV

Il< lIl < IV

answer is C.

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Detailed Solution

Allyl bromide (I) is most reactive among the given halides as pi bonds from allylic position stabilies the transition state. Vinyl iodide (II) is least reactive due to partial double bond character. Electron withdrawing inductive effect of NO2 increases reactivity of (IV) over (III)

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