First slide

Acidic buffer

Question

What is the difference in pH for 1/3 and 2/3 stages of neutralization of 0.1 M ${CH}_{3} COOH$ with 0.1 M NaOH ?

Moderate

A

2 log 3
B

2 log (1/4)
C

2 log (2/3)
D

2 log 2

Solution

${CH}_{3} COOH + O H^{-} \overset{}{\to} {CH}_{3} {COO}^{-} + H_{2} O$
Difference in pH between $\frac{1}{3} and \frac{2}{3}$ stages of neutralization
$= [{pK}_{a} + \log (\frac{2 / 3}{1 / 3})] - {pK}_{a} - \log (\frac{1 / 3}{2 / 3}) = 2 \log 2$

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