What is the difference in pH for 1/3 and 2/3 stages of neutralization of 0.1 M CH3COOH with 0.1 M NaOH ?

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2 log 3

2 log (1/4)

2 log (2/3)

2 log 2

answer is D.

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Detailed Solution

CH3COOH + OH-→ CH3COO- + H2ODifference in pH between 13 and 23 stages of neutralization= pKa + log 2/31/3 - pKa - log 1/32/3 = 2 log 2

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