what is the empirical formula of vanadium oxide, if 2.74 g of the metal oxide contains 1.53 g of metal ?

Metal oxide = 2.74 g;wt. of vanadium = 1.53 g % of V=1.532.74×100=55.83Thus, % of O = 100  -55.83=44.17No. of moles of V=55.8352=1.1No. of mores of O=44.1716=2.76Simplest ratio of V and O = 1:2.5 or 2 :5Hence, the empirical formula : V2O5