What is the empirical formula of vanadium oxide if 2.74g of the proof vests is 55.83% of V, 44.17% of O?( at.wt=51 for V)

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V2O3

V2O5

V2O7

answer is C.

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Detailed Solution

Mass of oxide =mass of metal +mass of oxygen2.74=1.53+Woxygen ⇒Woxygen =1.21 g moles of V=1.5351=0.03 moles of O=1.2116=0.075V0.03O0.075=V2O5

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