What is the equivalent weight of HNO3 in the given reaction ?4Zn + 10HNO3 → 4ZnNO32 + NH4NO3 + 3H2O
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a
6310
b
639
c
638 × 9
d
634 × 14
answer is C.
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Detailed Solution
(3)HNO3→NH4+N5+ + 8e- → N3-n-factor as reductant=89 moles of HNO3 is acting as acid, basicity is 1. As an acid, equivalent weight = MTotal equivalent weight = M (as acid) +M8( as Reducing agent)=9M8=9×638