Q.

What is the formula of the compound Prussian blue formed in the test of nitrogen ?

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a

Fe(CNS)3

b

Fe4Fe[CN)63

c

Fe2SO43

d

Fe3Fe(CN)62

answer is B.

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Detailed Solution

Fe2+⟶H+Fe3++e-;  6CN-+Fe2+⟶Fe(CN)64-3Fe(CN)64-+4Fe3+⟶Fe4III[FeII(CN)6]3Prussian blue (X)Fe3++3CNS−→FeCNS3Blood red (Y and Z)
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