What freezing point depression would be predicted for 0.2 molal solution of benzoic acid in benzene if latent heat of fusion is 40.00 cal g−1 at 280 K (freezing point) for benzene? (assume no change in molecular state)

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0.52o

5.2o

0.0052o

0.78o

answer is D.

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Detailed Solution

To=Freezing point of solvent ΔHf=Latent heat of fusionKf=RT021000ΔHf=2×(280)21000×40=15680040000=3.92 K mol−1 kgΔTf=molality×Kf=0.2×3.92=0.78o

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