What freezing point depression would be predicted for 0.2 molal solution of benzoic acid in benzene if latent heat of fusion is 40.00 cal g−1 at 280 K (freezing point) for benzene? (assume no change in molecular state)
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a
0.52o
b
5.2o
c
0.0052o
d
0.78o
answer is D.
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Detailed Solution
To=Freezing point of solvent ΔHf=Latent heat of fusionKf=RT021000ΔHf=2×(280)21000×40=15680040000=3.92 K mol−1 kgΔTf=molality×Kf=0.2×3.92=0.78o