Q.

What is the lowest energy of the spectral line emitted by the hydrogen atom in the Lyman series?(h = Planck constant, c = Velocity of light,R = Rydberg constant)

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a

b

c

d

answer is C.

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Detailed Solution

Lowest energy is emitted when n2=n1+1 Thus in Lyman series 2 → 1 will have least energy                                                                                    E=3hcRH4
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What is the lowest energy of the spectral line emitted by the hydrogen atom in the Lyman series?(h = Planck constant, c = Velocity of light,R = Rydberg constant)