What mass of urea be dissolved in 171 g of water so as to decrease the vapour pressure of water by 5%?
15 g
20 g
25 g
30 g
∆PPA°=XB=0.05 (given) 0.05 =nBnB+nA=nBnB+17118 ⇒nB = 0.5 ⇒Wurea= 0.5×60= 30 g