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Q.

What mass of urea be dissolved in 171 g of water so as to decrease the vapour pressure of water by 5%?

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a

15 g

b

20 g

c

25 g

d

30 g

answer is D.

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Detailed Solution

∆PPA°=XB=0.05 (given) 0.05 =nBnB+nA=nBnB+17118 ⇒nB = 0.5 ⇒Wurea= 0.5×60= 30 g
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