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What is the molar solubility of is
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a
8.0×10−18
b
8.0×10−15
c
8.0×10−17
d
8.0×10−14
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Correct option is D
Fe(OH)2→Fe2++2OH−PH+POH=14PH=13⇒POH=1⇒OH−=10−1⇒2s=OH−=10−1KSp=Fe+2OH−2⇒8×10−16=(S)10−1)2⇒S=8×10−14Similar Questions
The solubility of Ag2CO3 in water at 25°C is 1×10-4 mole / litre. The solubility in 0.01 M Na2CO3 solution is x × 10-5 where x is ________.
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