What is the molar solubility of FeOH2Ksp=8.0×10−16 is pH= 13.0?

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8.0×10−18

8.0×10−15

8.0×10−17

8.0×10−14

answer is D.

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Detailed Solution

Fe(OH)2→Fe2++2OH−PH+POH=14PH=13⇒POH=1⇒OH−=10−1⇒2s=OH−=10−1KSp=Fe+2OH−2⇒8×10−16=(S)10−1)2⇒S=8×10−14