What is the molarity of K+ in aqueous solution that contains 17.4 ppm of K2SO4 (molar mass = 174 g mo-1) ?

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2×10−2M

2×10−3M

4×10−4M

2×10−4M

answer is D.

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Detailed Solution

K2SO4 is 17.4ppm, i.e. 106g has 17.4gK2SO41L103mL has K2SO4=17.4×103106=0.0174g/L =0.0174174mol/L∴ K2SO4=1×10−4M K2SO4⇌2K++SO42∴ K+=2×10−4M

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