First slide

PH of strong acids and strong bases

Question

What is the ${[OH]}^{-}$ in the final solution prepared by mixing 20.0 mL of 0.050 M HCl with 30.0 mL of 0.10 M $Ba {(OH)}_{2} ?$

Moderate

A

0.10 M
B

0.40 M
C

0.0050 M
D

0.12 M

Solution

Number of milliequivalent of HCl = 20 x 0.050 x 1 = 1
Number of milliequivalent of $Ba {(OH)}_{2}$ = 2 x 30 x 0.1 = 6
$[{OH}^{-}] of final solution = \frac{milliequivalents of Ba {(OH)}_{2} - milliequivalent of HCl}{total volume}$
$= \frac{6 - 1}{50} = 0.1 M$

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