What is the order of reaction for which rate becomes half if volume of the container having same amount of reactant is doubled? Assume gaseous phase reaction.
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answer is 1.
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Detailed Solution
Rate =k[a]nCase I : r1=kaVn . . . (i) Case II: r12=ka2Vn . . . (ii)By Eqs. (i) and (ii)21=2n ∴ n = 1
What is the order of reaction for which rate becomes half if volume of the container having same amount of reactant is doubled? Assume gaseous phase reaction.