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Q.

What is the oxidation state of 'Fe' in the product formed when acidified potassium ferrocyanide K4[Fe(CN)6] is treated with hydrogen peroxide?

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a

+2

b

+3

c

+1

d

+6

answer is B.

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Detailed Solution

In K4[Fe(CN)6] Ox.state of 'Fe' is +2[Fe(CN)6]-4x + 6(-1) = -4x = +2H2O2 Oxidises K4[Fe(CN)6] to K3[Fe(CN)6] in acidic medium  In  K3[Fe(CN)6] ,[Fe(CN)6]-3x +6(-1) = -3x = +3
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