What is the PHof a buffer containing 0.09 M CH3COOH and 0.15 M of potassium acetate? Ka=1.8×10-5, log 5=0.699, log 3 =0.4771, log 1.8=0.2553
4.97
4.70
7.04
3.40
PH=PKa+logsaltacid
=-log1.8×10-5+log0.150.09
=-0.2553-5+log 5-log 3
=+4.7447+0.699-0.4771
=4.9666