What is the pH of a 1 M CH3COOH a solution Ka of acetic acid = 1.8 × 10-5 ?
K = 10-14 mol2 litre-2
9.4
4.8
3.6
2.4
CH3COO- + H2O ⇌ CH3COOH + OH-
OH- = c × h; h = KwKa × c = 10-141.8 ×10-5 ×1 =2.35 × 10-5 ∴ pOH=4.62; pH = 9.38 ≈ 9.4